Codechange: add concept of ConvertibleThroughBase for strong types
This makes it possible to write templated alternatives for ConvertibleThroughBase which are then available for any (strong) type that implements a base() function In the end making adding new ConvertibleThroughBase types less awkward.
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+8
-8
@@ -11,11 +11,11 @@
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#define FORMAT_HPP
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#include "../3rdparty/fmt/format.h"
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#include "strong_typedef_type.hpp"
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#include "convertible_through_base.hpp"
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template <typename E, typename Char>
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struct fmt::formatter<E, Char, std::enable_if_t<std::is_enum<E>::value>> : fmt::formatter<typename std::underlying_type<E>::type> {
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using underlying_type = typename std::underlying_type<E>::type;
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template <typename E, typename Char> requires std::is_enum_v<E>
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struct fmt::formatter<E, Char> : fmt::formatter<typename std::underlying_type_t<E>> {
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using underlying_type = typename std::underlying_type_t<E>;
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using parent = typename fmt::formatter<underlying_type>;
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constexpr fmt::format_parse_context::iterator parse(fmt::format_parse_context &ctx)
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@@ -23,14 +23,14 @@ struct fmt::formatter<E, Char, std::enable_if_t<std::is_enum<E>::value>> : fmt::
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return parent::parse(ctx);
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}
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fmt::format_context::iterator format(const E &e, format_context &ctx) const
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fmt::format_context::iterator format(const E &e, fmt::format_context &ctx) const
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{
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return parent::format(underlying_type(e), ctx);
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}
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};
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template <typename T, typename Char>
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struct fmt::formatter<T, Char, std::enable_if_t<std::is_base_of<StrongTypedefBase, T>::value>> : fmt::formatter<typename T::BaseType> {
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template <ConvertibleThroughBase T, typename Char>
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struct fmt::formatter<T, Char> : fmt::formatter<typename T::BaseType> {
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using underlying_type = typename T::BaseType;
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using parent = typename fmt::formatter<underlying_type>;
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@@ -39,7 +39,7 @@ struct fmt::formatter<T, Char, std::enable_if_t<std::is_base_of<StrongTypedefBas
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return parent::parse(ctx);
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}
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fmt::format_context::iterator format(const T &t, format_context &ctx) const
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fmt::format_context::iterator format(const T &t, fmt::format_context &ctx) const
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{
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return parent::format(t.base(), ctx);
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}
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