Codechange: use Date/Year constructor explicitly

This commit is contained in:
Rubidium
2025-01-01 09:13:39 +01:00
committed by rubidium42
parent f55ba40b13
commit 3956ed086a
22 changed files with 46 additions and 48 deletions

View File

@@ -68,28 +68,28 @@ template <class T>
*/
/* There are 97 leap years in 400 years */
Year yr = 400 * (date.base() / (TimerGameConst<T>::DAYS_IN_YEAR * 400 + 97));
Year yr{400 * (date.base() / (TimerGameConst<T>::DAYS_IN_YEAR * 400 + 97))};
int rem = date.base() % (TimerGameConst<T>::DAYS_IN_YEAR * 400 + 97);
if (rem >= TimerGameConst<T>::DAYS_IN_YEAR * 100 + 25) {
/* There are 25 leap years in the first 100 years after
* every 400th year, as every 400th year is a leap year */
yr += 100;
yr += Year{100};
rem -= TimerGameConst<T>::DAYS_IN_YEAR * 100 + 25;
/* There are 24 leap years in the next couple of 100 years */
yr += 100 * (rem / (TimerGameConst<T>::DAYS_IN_YEAR * 100 + 24));
yr += Year{100 * (rem / (TimerGameConst<T>::DAYS_IN_YEAR * 100 + 24))};
rem = (rem % (TimerGameConst<T>::DAYS_IN_YEAR * 100 + 24));
}
if (!IsLeapYear(yr) && rem >= TimerGameConst<T>::DAYS_IN_YEAR * 4) {
/* The first 4 year of the century are not always a leap year */
yr += 4;
yr += Year{4};
rem -= TimerGameConst<T>::DAYS_IN_YEAR * 4;
}
/* There is 1 leap year every 4 years */
yr += 4 * (rem / (TimerGameConst<T>::DAYS_IN_YEAR * 4 + 1));
yr += Year{4 * (rem / (TimerGameConst<T>::DAYS_IN_YEAR * 4 + 1))};
rem = rem % (TimerGameConst<T>::DAYS_IN_YEAR * 4 + 1);
/* The last (max 3) years to account for; the first one